2018 Boyd Tinsley Clay Court Classic – Doubles

Jovana Jakšić and Catalina Pella were the defending champions, but decided not to participate.

Doubles
2018 Boyd Tinsley Clay Court Classic
Champions	Sophie Chang Alexandra Mueller
Runners-up	Ashley Kratzer Whitney Osuigwe
Final score	3–6, 6–4, [10–7]

Sophie Chang and Alexandra Mueller won the title after defeating Ashley Kratzer and Whitney Osuigwe 3–6, 6–4, [10–7] in the final.

Seeds

Irina Bara / Mariana Duque Mariño (semifinals)
Alexa Guarachi / Erin Routliffe (quarterfinals)
Sophie Chang / Alexandra Mueller (champions)
Paula Cristina Gonçalves / Sanaz Marand (first round)

Draw

Key

Draw

	First round							Quarterfinals							Semifinals							Final

	1	I Bara M Duque Mariño	6	6
		K Cartwright K Pierre-Louis	3	1				1	I Bara M Duque Mariño	2	7	[10]
	WC	A Smith N Subhash	6	6				WC	A Smith N Subhash	6	5	[5]
		M Mateas R Yurovsky	2	4											1	I Bara M Duque Mariño	6	4	[4]
	3	S Chang A Mueller	6	6											3	S Chang A Mueller	1	6	[10]
		L Chirico F Di Lorenzo	3	3				3	S Chang A Mueller	7	6
		P Januskova R Ozaki	4	6	[7]				C Rosatello AS Sánchez	5	2
		C Rosatello AS Sánchez	6	3	[10]																	3	S Chang A Mueller	3	6	[10]
		V Duval J Loeb	6	4	[10]																		A Kratzer W Osuigwe	6	4	[7]
		Q Gleason A Weinhold	2	6	[8]				V Duval J Loeb	6	6²	[10]
		A Kratzer W Osuigwe	6	6					A Kratzer W Osuigwe	3	7⁷	[12]
	4	PC Gonçalves S Marand	3	4												A Kratzer W Osuigwe	6	2	[12]
		J Cristian K Day	1	3												I Neel M Sanchez	4	6	[10]
		I Neel M Sanchez	6	6					I Neel M Sanchez	6	1	[20]
		R McAdoo K Stewart	6	4	[7]			2	A Guarachi E Routliffe	2	6	[18]
	2	A Guarachi E Routliffe	2	6	[10]

References

Main Draw

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