2019 Lale Cup – Doubles
Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.
| Doubles | |
|---|---|
| 2019 Lale Cup | |
| Champions | |
| Runners-up | |
| Final score | 7–5, 6–7(2–7), [10–5] |
Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7(2–7), [10–5].[1]
Seeds
Olga Doroshina /
Polina Monova (first round, withdrew)
Raluca Șerban /
Isabella Shinikova (semifinals)
Berfu Cengiz /
Jessy Rompies (semifinals)
Valentini Grammatikopoulou /
Ankita Raina (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | |||||||||||||||||||||||||||
| w/o | |||||||||||||||||||||||||||
| 7 | 4 | [8] | w/o | ||||||||||||||||||||||||
| 5 | 6 | [10] | 7 | 7 | |||||||||||||||||||||||
| 3 | 6 | 6 | 3 | 5 | 5 | ||||||||||||||||||||||
| WC | 3 | 4 | 3 | 1 | 6 | [11] | |||||||||||||||||||||
| 6 | 6 | 6 | 4 | [9] | |||||||||||||||||||||||
| WC | 3 | 3 | 7 | 62 | [10] | ||||||||||||||||||||||
| 6 | 6 | 5 | 77 | [5] | |||||||||||||||||||||||
| 2 | 3 | 4 | 6 | [11] | |||||||||||||||||||||||
| 7 | 6 | 6 | 3 | [9] | |||||||||||||||||||||||
| 4 | 5 | 4 | 66 | 6 | [11] | ||||||||||||||||||||||
| 6 | 77 | 2 | 78 | 3 | [9] | ||||||||||||||||||||||
| 1 | 63 | 6 | 62 | [7] | |||||||||||||||||||||||
| WC | 0 | 0 | 2 | 4 | 77 | [10] | |||||||||||||||||||||
| 2 | 6 | 6 | |||||||||||||||||||||||||
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